Answer:
a1 = 2, a2 = 4, a3 = 8, a4 = 16, and a5 = 32
Explanation:
Given the first term and the nth term of the sequence as;
[tex]\begin{gathered} a_1=2 \\ a_n=2a_{n-1} \end{gathered}[/tex]
Since the first term is given already to be 2, let's go ahead and find the 2nd term;
[tex]\begin{gathered} a_2=2a_{2-1} \\ a_2=2a_1 \\ a_2=2\ast2 \\ \therefore a_2=4_{} \end{gathered}[/tex]
The 3rd term will be;
[tex]\begin{gathered} a_3=2a_{3-1} \\ =2a_2 \\ =2\ast4 \\ \therefore a_3=8 \end{gathered}[/tex]
The 4th term can be found as follows;
[tex]\begin{gathered} a_4=2a_{4-1} \\ =2a_3 \\ =2\ast8 \\ \therefore a_4=16 \end{gathered}[/tex]
The 5th term can found as follows;
[tex]\begin{gathered} a_5=2a_{5-1} \\ =2a_4 \\ =2\ast16 \\ \therefore a_5=32 \end{gathered}[/tex]
