Let's take a look at our triangle:
Using the law of cosines, we'll get that:
[tex]G^2=F^2+H^2-2FH\cos \angle G[/tex]Solving for angle G, we'll get:
[tex]\begin{gathered} G^2=F^2+H^2-2FH\cos \angle G \\ \rightarrow2FH\cos \angle G^{}=F^2+H^2-G^2 \\ \rightarrow\cos \angle G=\frac{F^2+H^2-G^2}{2FH} \\ \\ \rightarrow\angle G=\cos ^{-1}\frac{F^2+H^2-G^2}{2FH} \end{gathered}[/tex]This way,
[tex]\begin{gathered} \angle G=\cos ^{-1}\frac{65^2+70^2-48^2}{2(65)(70)} \\ \\ \Rightarrow\angle G=41 \end{gathered}[/tex]
