We need two ordered pairs of the table
(12,6)=(x1,y1)
(14,8)=(x2,y2)
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-6}{14-12}=\frac{2}{2}=1[/tex]the equation is
[tex]\begin{gathered} y-6=1(x-12) \\ y=x-12+6 \\ y=x-6 \end{gathered}[/tex]the equation is
y=x-6