Respuesta :
ANSWER
The two numbers are 128 and 128
EXPLANATION
Let the two numbers be x and y.
We have that:
[tex]\begin{gathered} x+y=256 \\ x\cdot y=A \end{gathered}[/tex]where A is a maximum.
From the first equation:
[tex]x=256-y[/tex]Substitute that into the second equation:
[tex]\begin{gathered} (256-y)\cdot y=A \\ \Rightarrow256y-y^2=A \\ \Rightarrow y^2-256y+A=0 \end{gathered}[/tex]The equation above is a quadratic equation in the general form:
[tex]ax^2+bx+c=0[/tex]The parabola is downward facing and so, its vertex will be the maximum.
We can find the vertex (x, y) of the parabola by using:
[tex]x=\frac{-b}{2a}[/tex]In the case given, the vertex can be found by using:
[tex]\begin{gathered} y=\frac{-(-256)}{2(1)}=\frac{256}{2} \\ y=128 \end{gathered}[/tex]Recall that:
[tex]x=256-y[/tex]Therefore, we have that:
[tex]\begin{gathered} x=256-128 \\ x=128 \end{gathered}[/tex]Hence, the two numbers are 128 and 128.
