Given:
Tyee has 10 1/4 yards of ribbon to make bows.
The length of each bow = 3/5 yards
We will find the maximum number of bows by divided the total length by the length of one bow.
so, the number of bows will be as follows:
[tex]10\frac{1}{4}\div\frac{3}{5}=\frac{41}{4}\div\frac{3}{5}=\frac{41}{4}\times\frac{5}{3}=\frac{205}{12}=17\frac{1}{12}[/tex]The number of bows will be an integer number
so, the answer will be:
The maximum number of complete bows = 17
