The number less than 3 are {1,2}.
The total possible outcome is 4.
Determine the probability for number less than 3.
[tex]\begin{gathered} P(A)=\frac{2}{4} \\ =\frac{1}{2} \end{gathered}[/tex]
The number divisor of 20 are {1,2,4}.
Determine the probability for landing on a number divisor of 20.
[tex]P(B)=\frac{3}{4}[/tex]
The probability for number less than 3 and number divisor of 20 are independent events. So,
[tex]\begin{gathered} P(AandB)=P(A)\cdot P(B) \\ =\frac{1}{2}\cdot\frac{3}{4} \\ =\frac{3}{8} \end{gathered}[/tex]
Determine the probability in percentage by multiply the fraction with 100.
[tex]\begin{gathered} P(AandB)=\frac{3}{8}\cdot100 \\ =37.5 \end{gathered}[/tex]
So answer is 37.5 %.
