According to the given data we have the following:
[tex]C=\frac{5}{9}(f-32)[/tex]In order to isolate F in the equation we would make the following:
First we would have the following property:
[tex]\frac{a}{b}=\frac{m}{n}=a\cdot n=b\cdot m[/tex]Therefore 9C=5f-160
9C+160=5f
So:
[tex]\begin{gathered} \frac{9C\text{ + 160}}{5}=f \\ \frac{9}{5}C+32=f \end{gathered}[/tex]