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to a certain meeting room a college charge a reservation fee of $37 and a ln additional fee of $9.40 per hour. the math club wants to spend less than $ 93.40 on renting the meeting room. what are the possible amounts of time for which they could rent the meeting room. use t for the number of hours the meeting room is rented and solve your inequality for t

Respuesta :

For the information given in the statement, you have the inequality:

[tex]\text{ \$37+\$9.40t < \$93.40}[/tex]

Now, to solve the inequality, subtract $37 from both sides of the inequality.

[tex]\begin{gathered} \text{ \$37+\$9.40t -\$37< \$93.40 - \$37} \\ \text{ \$9.40t < \$}56.4 \end{gathered}[/tex]

Now, divide by $9.40 into both sides of the inequality

[tex]\begin{gathered} \text{ \$9.40t < \$}56.4 \\ \frac{\text{ \$9.40t }}{\text{ \$9.40}}\text{< }\frac{\text{\$}56.4}{\text{ \$9.40}} \\ t<6 \end{gathered}[/tex]

Therefore, the math club could rent the meeting room for a maximum of 6 hours.