The airplane rises at an angle of 14° with respect to the ground.
You have to find the distances (diagonal) that it frew if it covered a horizontal distance of 1500 feet.
The distance flew by the place with respect to the horizontal ground and the height the plane is at after traveling 1500 feet form a right triangle. Where x represents the hypothenuse of the triangle. To determine its measure, you have to use the trigonometric relations
[tex]\begin{gathered} \sin \theta=\frac{opposite}{hypohtenuse} \\ \cos \theta=\frac{adjacent}{hypothenuse} \\ \tan \theta=\frac{opposite}{adjacent} \end{gathered}[/tex]Given that θ=14° and we know that the adjacent side to the angle measures 1500 feet, using the cosine we can determine the length of x as:
[tex]\begin{gathered} \cos 14=\frac{1500}{x} \\ x\cos 14=1500 \\ x=\frac{1500}{\cos 14} \\ x=1545.92ft \end{gathered}[/tex]The distance flew by the airplane is 1545.92ft
