On election day the polls open at 7:30 am and closes at 9pm. Marlene worked all day exceptfor a break at lunch 10:30 am to 12 pm and dthen break for dinner at 5:30 pm to 7 pm. Marleneworked What fraction of the time that the polls were open?(a) 4/7(b) *(C) ?(d)?(e) ?

Respuesta :

ANSWER;

The fraction of the time she worked was 7/9 of the time the polls were opened

EXPLANATION;

Here, we want to get the fraction of the time in which Marlene worked

What we have to do here is to calculate the total time the pool was opened, then calculate the total time in which she went for break. Then we divide the break time by the total opening time

We proceed as follows;

From 7 : 30 am to 9pm

7:30 am to 9:30 pm is 14 hours

Kindly note that we are to subtract 30 minutes, so we have the total time as 13 hours and 30 minutes

For ease of calculations, we shall have all the time in minute

Recall, 60 minutes are in an hour

So, in 13 hours, we have 13(60) = 780 minutes

Added to the 30, we have a total of 780 minutes + 30 minutes = 810 minutes

Break Times

The first break is 10; 30 am to 12 pm; that is a total time of 1 hour 30 minutes

The second break is from 5:30 pm to 7 pm; that is another 1 hour 30 minutes

Total time spent on breaks is 3 hours

Converting to minutes, we simply multiply by 60 and that will give 3(60) = 180 minutes

Thus, we can now proceed to divide;

[tex]\frac{180}{810}\text{ = }\frac{6}{27}\text{ = }\frac{2}{9}[/tex]

The above is the fraction spent on breaks. To get the farction worked, we simply subtract the above fraction from 1

We have this as;

[tex]1\text{ - }\frac{2}{9}\text{ = }\frac{7}{9}[/tex]