ANSWER:
6 m/s
STEP-BY-STEP EXPLANATION:
Given:
Mass of balls (m) = 3.86 kg
Initial speed of ball 1 (u1) = 5 m/s
Final speed of ball 1 (v1) = - 1 m/s
Initial speed of ball 2 (u2) = 0 m/s
We make the balance for the moment and we are left with the following:
[tex]\begin{gathered} m_1\cdot u_1+m_2\cdot u_2=m_1\cdot v_1+m_2\cdot v_2 \\ \\ \text{ We repalcing:} \\ \\ 3.86\cdot5+3.86\cdot0=3.86\cdot-1+3.86\cdot v_2 \\ \\ 19.3=-3.86+3.86v_2 \\ \\ 3.86v_2=19.3+3.86 \\ \\ v_2=\frac{23.16}{3.86} \\ \\ v_2=6\text{ m/s} \end{gathered}[/tex]Therefore, the speed of the second ball is equal to 6 m/s