Answer:
[tex]3.87*10^{23}atoms[/tex]
Explanations:
Given the following parameters
Mass of hydrazine = 19.3 grams
Determine the moles of hydrazine
[tex]\begin{gathered} moles\text{ of N}_2H_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of N}_2H_2=\frac{19.3}{30.02928} \\ moles\text{ of N}_2H_2=0.6423moles \end{gathered}[/tex]
According to the Avogadro's constant
[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex][tex]\begin{gathered} atoms\text{ of N}_2H_2=0.643\times6.02\times10^{23} \\ atoms\text{ of N}_2H_2=3.87\times10^{23}atoms \end{gathered}[/tex]
Therefore the total atoms that are there in 19.3 g of hydrazine is 3.87 * 10^23 atoms
