Let's label the diagram with the information provided. The diagram would look like:
What is the horizontal distance between anchor 1 and the base of the antenna?
This is labeled as x.
With respect to angle alpha, the side x is opposite and the antenna is the side adjacent.
Thus, we need the trig ratio tan to solve for "x". Shown below:
[tex]\begin{gathered} \tan \alpha=\frac{x}{170} \\ \tan (0.33)=\frac{x}{170} \\ x=170\times\tan (0.33) \\ x=58.23 \end{gathered}[/tex]
Answer: 58.23 feet
What is the horizontal distance between anchor 2 and the base of the antenna?
This is labeled as y.
With respect to angle beta, the side y is opposite and the antenna is the side adjacent.
Thus, we need the trig ratio tan to solve for "y". Shown below:
[tex]\begin{gathered} \tan \beta=\frac{y}{170} \\ \tan (0.43)=\frac{y}{170} \\ y=170\times\tan (0.43) \\ y=77.97 \end{gathered}[/tex]
Answer: 77.97 feet
What is the distance between anchor 1 and anchor 2?
The distance between Anchor 1 and Anchor 2 is "x + y". We already found x and y. Let's do the sum:
[tex]\begin{gathered} x+y \\ =58.23+77.97 \\ =136.2 \end{gathered}[/tex]
Answer: 136.2 feet
