A racecar travels around a circular track of radius 400 meters at constant speed. If the car's acceleration is 4 m/s2, what is its speed?

Respuesta :

We are given that a car travels in a circular motion with an acceleration of 4m/s^2. We are asked to determine the speed of the motion. To do that we will use the following formula:

[tex]a=\frac{v^2}{r}[/tex]

Where:

[tex]\begin{gathered} a=\text{ acceleration} \\ v=\text{ velocity} \\ r=\text{ radius} \end{gathered}[/tex]

We will solve for the velocity first by multiplying both sides by "r":

[tex]ar=v^2[/tex]

Now we take the square root to both sides:

[tex]\sqrt[]{ar}=v[/tex]

Now we plug in the values:

[tex]\sqrt[]{(4\frac{m}{s^2})(400m)}=v[/tex]

Now we solve the operations:

[tex]40\frac{m}{s}=v[/tex]

Therefore, the velocity of the car is 40 meters per second.