Given the length and the expression that represents the width of a rectangle, you need to remember that:
• The area of a rectangle can be calculated by multiplying its dimensions:
[tex]A=lw[/tex]Where "l" is the length and "w" is the width.
• The perimeter of a rectangle is:
[tex]P=2l+2w[/tex]Where "l" is the length and "w" is the width.
Then, knowing that:
[tex]\begin{gathered} l=5 \\ w=x+2 \end{gathered}[/tex]- You can set up that the area of this rectangle is:
[tex]A=5(x+2)[/tex]Simplifying, you get:
[tex]\begin{gathered} A=(5)(x)+(5)(2) \\ A=5x+10 \end{gathered}[/tex]- And the perimeter is:
[tex]\begin{gathered} P=(2)(5)+(2)(x+2) \\ P=10+2x+4 \\ P=2x+14 \end{gathered}[/tex]Hence, the answer is:
- The area is:
[tex]A=5x+10[/tex]- The perimeter is:
[tex]P=2x+14[/tex]