Answer and Explanation
(a) At constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.
P = n (RT/V) where P is the pressure, n is the number of moles, R is the gas constant, T is the temperature and V is the volume
So when the pressure in increased, the volume will be decreased, meaning there will be less space in the container, this will lead to more collisions inside a container, meaning, the number of moles will be increased.
[tex]\frac{P_1}{n_1}\text{ = }\frac{P_2}{n_2}[/tex](b) Given: initial number of moles (n1) = 4.0 moles
initial pressure (P1) = 1.6 atm
Final number of moles (n2) = 3.0 moles
Required: Final Pressure (P2)
solution
P1/n1 = P2/n2
P2 = P1*n2/n1
P2 = 1.6 atm*3.0 moles/4.0 moles
P2 = 1.2 atm