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Use Polya's four-step problem-solving strategy to solve the following exercise.A frog is at the bottom of a 13-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of the well, then the frog slides back 1 foot before it is ready to make another leap. How many leaps will the frog need to escape the well?______ leaps

Respuesta :

ANSWER:

6 leaps

STEP-BY-STEP EXPLANATION:

Keep adding 2 until the sum is 10 and count the number of 2 that has been added. Then add 1 to that number, as the last jump will cover the remaining 3 feet and the frog will reach the top of the well.

[tex]\begin{gathered} 2+2+2+2+2=10 \\ 5\text{ leaps} \end{gathered}[/tex]

Carry out the plan

The number of 2 added is 5.

Add 1 to the number 5.

5+1 = 6

Hence, the total number of leaps is 7.

For 1st leap

3- 1 = 2

For 2nd leap

2+3 = 5-1 = 4

For 3rd leap

4+3=7-1 = 6

For 4th leap

6+3=9-1 = 8

For 5th leap

8+3=11-1=10

For 6th leap

10+3 = 13

Hence, the total number of leaps is 6

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