Given that
It is said that we have to find the amount by which the radius will be increased such that the area is increased by 10 times.
Explanation -
The formula for the area of the circle is given as
[tex]\begin{gathered} Area=\pi\times r^2 \\ \\ A=\pi r^2-----------(i) \\ \\ where\text{ r is the radius of the circle.} \end{gathered}[/tex]Now the new area is 10 times the previous one.
Let the new area be A' and the new radius be R.
Then,
[tex]\begin{gathered} A^{\prime}=\pi\times R^2 \\ \\ As\text{ A'=10}\times A \\ \\ Then\text{ substituting the value of A' we have} \\ \\ 10\times A=\pi\times R^2 \end{gathered}[/tex]Now again substituting the value of A we have
[tex]\begin{gathered} \pi\times R^2=10\times\pi\times r^2 \\ \\ R^2=10r^2 \\ \\ R=\sqrt{10}\times r \end{gathered}[/tex]Hence the new radius will be √10 times the initial radius such that the area gets increased by 10 times.
Final answer - Therefore the final answer is √10 times.