since the rectangles are similar then
[tex]\begin{gathered} \frac{length\text{ of rectangle 1}}{width\text{ of rectangle 1}}=\text{ }\frac{length\text{ of rectngle 2 }}{width\text{ of rectangle 2}} \\ \end{gathered}[/tex]using the information from the question
length of rectangle 1 = 22cm
width of rectancle 1 = 4cm
Length of rectangle 2 = xcm
width of rectangle 2 = 6cm
using the above formula
[tex]\begin{gathered} \frac{22}{4}\text{ = }\frac{x}{6} \\ \frac{11}{2}\text{ = }\frac{x}{6} \\ \text{cross multiply } \\ 66\text{ = 2x} \\ \text{divide both sides by 2} \\ x\text{ = 33cm} \end{gathered}[/tex]this implies
lengt of rectangle 2 = 33cm
now we aply perimeter of rectangle
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