A
Since AB in perpendicular to CD and bisects mThis can be written as
[tex]m<\text{MOP}+m<\text{COM}+m<\text{DOP}=180\text{ (1)}[/tex]
but
[tex]m<\text{COM}=m<\text{DOP}[/tex]
then
[tex]m<\text{MOP}+2m<\text{DOP}=180[/tex]
pluggin the value of the angle m[tex]\begin{gathered} 130+2m<\text{DOP}=180 \\ 2m<\text{DOP}=180-130 \\ m<\text{DOP}=\frac{50}{2} \\ m<\text{DOP}=25 \end{gathered}[/tex]Therefore the angle m
B
As we mentioned above the angle mthen m
Using equation (1) of part to find the angle m[tex]\begin{gathered} m<\text{MOP}+38+38=180 \\ m<\text{MOP}=180-76 \\ m<\text{MOP}=104 \end{gathered}[/tex]therefore the angle m
