You have one type of chocolate that sells for $5.00/lb and another type of chocolate that sells for $7.60/lb. You would like to have 10.4 lbs of a chocolate mixture that sells for $6.50/lb. How much of each chocolate will you need to obtain the desired mixture? You will need BLANK lbs of the cheaper chocolate and BLANK lbs of the expensive chocolate.Please help!! It is urgent.

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Answer

You will need 4.4 lbs of the cheaper chocolate and 6 lbs of the expensive chocolate.

Explanation

Let the amount to be made of the type of chocolate (cheaper chocolate) that sells for $5.00/lb be x pounds.

Let the amount to be made of the type of chocolate (expensive chocolate) that sells for $7.60/lb be y pounds.

We would like to make a chocolate mixture that weighs 10.4 lbs. That is,

x + y = 10.4 .......... equation 1

This chocolate mixture is supposed to cost $6.50/lb and weigh 10.4 lbs. Hence, the cost of 10.4 lbs of this chocolate mixture will be

= 6.50 × 10.4 = $67.6

The cost of x pounds of the $5.00/lb = x × 5 = 5x dollars

The cost of y pounds of the $7.60/lb = y × 7.60 = 7.6y dollars

The cost of the two types of chocolate have to amount to $67.6

5x + 7.6y = 67.6 .......... equation 2

Writing the two equations together

x + y = 10.4

5x + 7.6y = 67.6

This simultaneous equation is then solved and the solution obtained is

x = 4.4 pounds and y = 6 pounds.

Hope this Helps!!!