Given the equation:
[tex]x+4y=16[/tex]to find the first value, we have to make x = 0 and solve for y, then, we have the following:
[tex]\begin{gathered} x=0 \\ \Rightarrow0+4y=16 \\ \Rightarrow4y=16 \\ y=\frac{16}{4}=4 \\ y=4 \end{gathered}[/tex]then, on the first row, the value of y is 4.
For the next two, notice that we now have values for y, this means that we have y = 0 and y = 1. Solving each case for x, we get:
[tex]\begin{gathered} y=0 \\ \Rightarrow x+4(0)=16 \\ x=16 \end{gathered}[/tex]and
[tex]\begin{gathered} y=1 \\ \Rightarrow x+4(1)=16 \\ \Rightarrow x=16-4=12 \\ x=12 \end{gathered}[/tex]therefore, the table should look like this:
