A car company charges $42.50 per day to rent a car in 10 since for every mile driven Lydia wants to rent a car knowing that she plans to drive 225 miles and she has at most a $150 to spend

A car company charges 4250 per day to rent a car in 10 since for every mile driven Lydia wants to rent a car knowing that she plans to drive 225 miles and she h class=

Respuesta :

Explanation:

d: number of days.

m: number of miles.

The total cost of the car 'y' is:

[tex]y=42.5d+0.1m[/tex]

Lydia plans to drive 225 miles, this is m = 225. And she has $150 to spend, so we have to solve y ≤ 150.

The inequality to solve is:

[tex]\begin{gathered} y\le150 \\ 42.5d+0.1\cdot225\le150 \\ 42.5d+22.5\le150 \end{gathered}[/tex]

Solving the inequality:

[tex]\begin{gathered} 42.5d+22.5\le150 \\ 42.5d\le150-22.5 \\ 42.5d\le127.5 \\ d\le\frac{127.5}{42.5} \\ d\le3 \end{gathered}[/tex]

Lydia can afford 3 days at most.

Answers:

• Inequality: ,42.5d + 22.5 ≤ 150

,

• d ≤ 3