To solve the exercise it is easier to convert all the given points to decimals. So,
[tex]\frac{2}{7}=0.23[/tex][tex]\frac{6}{8}=0.75[/tex]Then,
*The point closest to the benchmark 1 is at 0.9.
*The point closest to the benchmark 0 is 0.1.
*Ordering these points from least to greatest you have:
[tex]\begin{gathered} 0.1 \\ 0.23=\frac{2}{7} \\ 0.75=\frac{6}{8} \\ 0.9 \end{gathered}[/tex]