Given:
[tex]\begin{gathered} 4x+3y=12 \\ 4x-3y=12 \end{gathered}[/tex]
Required:
To solve the system of equation using graph and to state whether the system is dependent, independent, or inconsistent.
Explanation:
Consider the equation
[tex]4x+3y=12[/tex]
When x=0,
[tex]\begin{gathered} 0+3y=12 \\ 3y=12 \\ y=\frac{12}{3} \\ y=4 \end{gathered}[/tex]
When x=3,
[tex]\begin{gathered} 12+3y=12 \\ 3y=12-12 \\ 3y=0 \\ y=0 \end{gathered}[/tex]
Now consider the equation
[tex]4x-3y=12[/tex]
When x=0,
[tex]\begin{gathered} 0-3y=12 \\ -3y=12 \\ y=-\frac{12}{3} \\ y=-4 \end{gathered}[/tex]
When x= 3,
[tex]\begin{gathered} 12-3y=12 \\ -3y=12-12 \\ -3y=0 \\ y=0 \end{gathered}[/tex]
The graph of the given system of equation is,
The blue graph is graph of 4x+3y=12 and the black graph is graph of
4x-3y=12.
The two line crosses at the point (3,0).
Therefore the solution is
[tex]\begin{gathered} x=3 \\ y=0 \end{gathered}[/tex]
Here the solution is one.
Therefore the consistent system has exactly one solution, it is independent .
Final Answer:
The solution of the given system of equation is
[tex]\begin{gathered} x=3 \\ y=0 \end{gathered}[/tex]
The consistent system has exactly one solution, it is independent .
