(x-2)
1) Let's use the Rational Roots Theorem so that we can factor this Polynomial and find the factors that make up this Polynomial.
2) Taking all the factors of the constant and the leading coefficients we have:
[tex]P(x)=3x^3-11x^2-2x+24[/tex]
Let's enlist these factors:
[tex]\begin{gathered} 24\colon\pm1,\pm2,\pm4,\pm3,\pm6,\pm8,\pm12,\pm24 \\ 3\colon\pm1,\pm3 \end{gathered}[/tex]
2.2) Let's pick any number on the numerator and divide it by any number of the denominator, to get possible roots:
[tex]\begin{gathered} \frac{\pm1,\pm2,\pm4,\pm3,\pm6,\pm8,\pm12,\pm24}{\pm1,\pm3}=\pm1,\pm2,\pm\frac{4}{3}, \\ \end{gathered}[/tex]
Proceeding with that let's do a Synthetic Division, testing 2
[tex]\begin{gathered} \frac{3x^3-11x^2-2x+24}{(x-2)}= \\ (x-2)(3x^2-5x-12) \\ (x-2)(3x+4)(x-3) \end{gathered}[/tex]
Note that we have three factors. After factoring out
3) Hence, the answer is (x-2)
