In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calrimetry question is:
Q = mcΔT
Where:
Q = is energy as Heat
m = mass in grams
c = is the specific heat capacity
ΔT = the change in temperature, calculated as Final Temperature - Initial T
We have:
m = 75.0 grams
c = for water is 4.184 J/g°C
ΔT = 27.5 - 100 = -72.5°C
Now adding these values into the formula:
Q = 75 * 4.184 * (-72.5)
Q = - 22750.5 Joules, or -22.75 kJ
