0.0000253moles
The decomposition of NI3 is given as shown below;
[tex]2NI_3(s)→N_2(g)+3I_2(g)[/tex]Given the following parameters
Mass of NI3 = 0.02 grams
Determine the moles of NI3
[tex]\begin{gathered} moles\text{ of NI}_3=\frac{mass}{molar\text{ mass}} \\ moles\text{ of NI}_3=\frac{0.02}{394.719} \\ moles\text{ of NI}_3=0.0000507moles \end{gathered}[/tex]Acoording to stochiometry, 2 moles of NI3 preoduces 1 mole of nitrogen. The mole of nitrogen produced is;
[tex]\begin{gathered} mole\text{ of nitrogen}=\frac{1}{2}\times0.0000597 \\ mole\text{ of nitrogen}=\text{0.0000253moles} \end{gathered}[/tex]Hence the moles of nitrogen produced is 0.0000253moles
