Answer:
a. 0.75 mol
Explanation:
From the balanced equation, we know that 1 mole of AgNO3 reacts with 1 mole of KCl to produce 1 mole of AgCl and 1 mole of KNO3.
Since the ratio between AgNO3 and KCl is 1:1, in this case potassium chloride will be the limiting reactant and silver nitrate will be the excess reactant.
So we have to use the initial moles of the limiting reactant to calculate the moles of product that will be produced.
From the stoichiometry of the reaction we know that from 1 mole of KCl, we can obtain 1 mole of AgCl, so here the ratio between KCl and AgCl is also 1:1, so the maximum amount of silver chloride that can be produced is 0.75moles, as we can see using a mathematical rule of three:
[tex]\begin{gathered} 1molKCl-1moleAgCl \\ 0.75molesKCl-x=\frac{0.75molesKCl*1moleAgCl}{1molKCl} \\ x=0.75molesAgCl \end{gathered}[/tex]