Answer:
A.y=-4/3x+13/3
Step-by-step explanation:
The equation of a line has the following format:
y = ax + b
In which a is the slope.
Perpendicular to y = 3/4x+ 1:
Two lines are perpendicular if the multiplication of their slopes is -1.
Here the slope is 3/4.
In the answer to this exercise, the slope is a.
So
[tex]\frac{3}{4}\ast a=-1[/tex][tex]\frac{3a}{4}=-1[/tex]Now, cross multiplication
3a = -4
a = -4/3
So, for now, the equation is:
y = (-4/3)x + b
Passes through (-5,11):
This means that when x = -5, y = 11. So
11 = (-4/3)*(-5) + b
11 = (20/3) + b
b = 11 - (20/3)
[tex]11-\frac{20}{3}=\frac{\frac{3}{1}\ast11-\frac{3}{3}\ast20}{3}=\frac{33-20}{3}=\frac{13}{3}[/tex]So the correct answer is:
A.y=-4/3x+13/3
