First, let's equal the expression to zero:
[tex]\begin{gathered} x^2-8x=10 \\ \rightarrow x^2-8x-10=0 \end{gathered}[/tex]Now, let's use the general formula for quadratic equations:
[tex]\begin{gathered} \text{For} \\ ax^2+bx+c=0 \\ \\ \rightarrow x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]This way,
[tex]\begin{gathered} x=\frac{-(-8)\pm\sqrt[]{(-8)^2-4(1)(-10)}}{2(1)} \\ \\ \rightarrow x=\frac{8\pm\sqrt[]{64+40}}{2} \\ \\ \rightarrow x=\frac{8\pm\sqrt[]{104}}{2} \\ \\ \rightarrow x=\frac{8\pm2\text{ }\sqrt[]{26}}{2} \\ \\ \Rightarrow x=4\pm\sqrt[]{26} \end{gathered}[/tex]Answer: Option 2
