To rewrite the fractions as fractions with the same denominator we have to determine the minimum number greater than 8 and 3 that can be exactly divided by 8 and 3 (LCM). Notice that the LCM of 8 and 3 is
[tex]24=8\cdot3.[/tex]
Because:
[tex]\begin{gathered} 8=2\cdot2\cdot2, \\ 3=3. \end{gathered}[/tex]
Therefore, we rewrite the given fractions as:
[tex]\begin{gathered} \frac{1}{3}=\frac{8}{24}, \\ \frac{3}{8}=\frac{9}{24}\text{.} \end{gathered}[/tex]
From the above fractions, we get that:
[tex]\frac{3}{8}>\frac{1}{3}\text{.}[/tex]
Answer:
a)
[tex]\begin{gathered} \frac{1}{3}=\frac{8}{24}, \\ \frac{3}{8}=\frac{9}{24}\text{.} \end{gathered}[/tex]
b)
[tex]\frac{1}{3}<\frac{3}{8}\text{.}[/tex]
