From the problem, we have the inequalities :
[tex]\begin{gathered} x+2y<6 \\ yNote that the boundary line is
dashed if the symbols are < or >.
Let's graph first the first inequality :
[tex]\begin{gathered} x+2y<6 \\ \text{Change the symbol into ''=''} \\ x+2y=6 \\ \text{Solve for the intercepts} \\ \text{when x = 0} \\ 0+2y=6 \\ y=\frac{6}{2}=3 \\ \\ \text{when y = 0} \\ x+2(0)=6 \\ x=6 \end{gathered}[/tex]
Plot the points (0, 3) and (6, 0)
The region will pass through the origin if (0, 0) satisfies the inequality.
Test for (0, 0)
[tex]\begin{gathered} x+2y<6\text{ } \\ 0+0<6 \\ 0<6 \\ \text{TRUE!} \end{gathered}[/tex]
Since it is true, the region will pass through the origin.
The graph will be :
Next is to graph the second inequality :
[tex]\begin{gathered} yPlot the points (0, -5) and (5, 0)
Check again origin (0, 0) to the inequality :
[tex]\begin{gathered} ySince it is false, the region will not pass through the origin.
Tha graph will be :
The solution to the system is the overlapping region between the two inequalities.
