Given
Mass of the object, m=5 kg
Length of the inclined plane, s=3m
Angle of inclination,
[tex]\theta=10^o[/tex]
To find
Calculate its speed just before it hits the ground.
Explanation
Here the acceleration is
[tex]\begin{gathered} a=gsin\theta \\ \Rightarrow a=9.8sin10^o \end{gathered}[/tex]
The initial velocity is zero.
So the final velocity is
[tex]\begin{gathered} v=\sqrt{2as} \\ \Rightarrow v=\sqrt{2\times9.8sin10^o\times3} \\ \Rightarrow v=3.19\text{ m/s} \end{gathered}[/tex]
Conclusion
The velocity before it hit the ground, A.3.19 m/s
