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‼️‼️IF ANSWERED W WORK SHOWN I WILL GIVE BRAINLIEST‼️‼️The electric field intensity between two large, parallel metal plates is 6000 N/C. The plates are 0.05 mapart. What is the electric potential difference between them?

Respuesta :

We have the next information

E= 6000 N/C

d=0.05m

In order to find the electric potential difference we have the next formula

[tex]\Delta V=Ed[/tex]

then we substitute the data given in the formula

[tex]\Delta V=(6000\frac{N}{C})(0.05m)=300\frac{J}{C}=300V[/tex]

The electric potential difference between them is 300 V

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