Respuesta :
Answer: 12.66%
First, we will solve the probability that 3 adults, 2 adults, 1 adult and no adult use their smartphones in meetings or classes,
To solve for this, we will use the following equation
[tex]11Cn\times0.49^n\times0.51^{11-n}[/tex]*Probability of adults using their phones for meetings or classes are 0.49.
1 - 0.49 = 0.51
*Probability of adults NOT using their phones are 0.51
Now, with the values of n at:
n = 0
n = 1
n = 2
n = 3
[tex]11Cn\times0.49^n\times0.51^{11-n}=11C0\times0.49^0\times0.51^{11-0}=0.0006[/tex][tex]11Cn\times0.49^n\times0.51^{11-n}=11C1\times0.49^1\times0.51^{11-1}=0.0064[/tex][tex]11Cn\times0.49^n\times0.51^{11-n}=11C2\times0.49^2\times0.51^{11-2}=0.0308[/tex][tex]11Cn\times0.49^n\times0.51^{11-n}=11C3\times0.49^3\times0.51^{11-3}=0.0888[/tex]Now, we will add these altogether to get the probability that fewer than 4 of them use their smartphones in meetings or classes.
[tex]0.0006+0.0064+0.0308+0.0888=0.1266=12.66\%[/tex]The answer would be 12.66%.
