Given:
[tex]y=x^2+4x+7[/tex]Find: the manimum value of the function.
Explanation:
[tex]\begin{gathered} y=x^2+4x+7 \\ y^{^{\prime}}=2x+4 \\ y^{^{\prime}}=0 \\ 2x+4=0 \\ x=-2 \end{gathered}[/tex]ar x=-2,
the function will be
[tex]\begin{gathered} y=x^2+4x+7 \\ y(-2)=(-2)^2+4(-2)+7 \\ =4-8+7 \\ =11-8 \\ =3 \end{gathered}[/tex]