The function f(x) is graphed below. 3 2 -5-5-3 -2 3 Using interval notation, the domain is: Using interval notation, the range is: Determine f(2)= Solve f(x) = 0 (enter as list of decimal numbers): The y-intercept is at coordinates: The x-intercepts are (enter as list of decimal coordinates): The zeros are (enter as list of decimal numbers): Over the interval [ - 4, – 2], the function is Select an answer v Over the interval [ - 2, – 1], the function is Select an answer v Over the interval ( - 1,2], the function is Select an answer v Over the interval (2, 4), the function is Select an answer v The minimum value is: The maximum value is:

The function fx is graphed below 3 2 553 2 3 Using interval notation the domain is Using interval notation the range is Determine f2 Solve fx 0 enter as list of class=

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Given,

The graph of the curve is shown in the question.

The domain of the function are the input value which are x coordinates values.

The range of the function are the output value which are represent by y coordinates of the graph.

So, from the graph its is clearly seen that the curve taking input from -4 to 4,

Hence, the domain of the function is,

[tex]\lbrack-4,4\rbrack[/tex]

So, from the graph its is clearly seen that the curve giving output from 3 to -1,

Hence, the range of the function is,

[tex]\lbrack-1,3\rbrack[/tex]

c) from the graph it is seen that when the value of x coordinate is 2 then the value of y coordinate is -1.

[tex]\text{Hence, f(2)=-1}[/tex]

The value of x when the coordinates of y is 0 at x=3, -1.5.

[tex]\text{Hence, f(3)=0 and f(-1.5)=0}[/tex]

The intercept of the y axis is at (0, -1).

The intercept of the x axis is at (-1.5,0) and (3,0).

The values at which y coordinate is zero is called the zeroes of the graph.

The xeroes of the graph is x=-1.5 and x=3.

In interval [-4,-2], the function is decreasing.

In interval [-2,-1] the function is decreasing.

In interval [-1,2] the function is contant.

ininterval [2,4] the function is increasing.

The maximum value of the graph is 3.

The minimum value of the graph is at -1