..Given: Two parallel lines BD and QS and a transversal AT
To Determine: The measure of CRQ and CRS
Solution
From the image given, angle DCR and CRQ are alternate angles
Also angle DCR and angle CRS are each pair of the same interior angles
Please note that alternates angles are equal and each pair of same-side interior angles are supplementary
Apply the theorem above
[tex]\begin{gathered} \angle CRQ=\angle DCR(alternate-angles) \\ \angle CRQ=77^0 \end{gathered}[/tex]
Also
[tex]\begin{gathered} \angle DCR+\angle CRS=180^0(same-ineterior-angles) \\ 77^0+\angle CRS=180^0 \\ \angle CRS=180^0-77^0 \\ \angle CRS=103^0 \end{gathered}[/tex]
Hence:
∠CRQ = 77⁰
∠CRS = 103⁰
