1. Reasons quantitatively. AB lies on the number line. The coordinate of point A is -6. Given thay AB = 20, what are two possible coordinates for point B?2. Given: Point K is between points H and J, HK = x - 5, KJ = 5x - 12, and HJ = 25. Find the value of x.

1 Reasons quantitatively AB lies on the number line The coordinate of point A is 6 Given thay AB 20 what are two possible coordinates for point B2 Given Point K class=

Respuesta :

The distance in a coordinate line is given by:

[tex]d(A,B)=\lvert B-A\rvert[/tex]

in this case we know that A=-6 and we would like to know the value of B so that the distance is 20. Plugging this values in the equation we have:

[tex]\begin{gathered} \lvert B-(-6)\rvert=20 \\ \lvert B+6\rvert=20 \end{gathered}[/tex]

Now we need to remember the property:

[tex]\begin{gathered} \lvert x\rvert=a \\ \text{implies} \\ x=\pm a \end{gathered}[/tex]

Using this we have:

[tex]\begin{gathered} \lvert B+6\rvert=20 \\ B+6=\pm20 \\ B=-6\pm20 \end{gathered}[/tex]

Then:

[tex]\begin{gathered} B=-6+20=14 \\ B=-6-20=-26 \end{gathered}[/tex]

Therefore the two possible coordinates for B are 14 and -26.