The sample space for one 6-sided die is given by
[tex]{}\lbrace1,2,3,4,5,6\rbrace[/tex]
Then, the probability to get the number 2 or a number less than 6 is given by
[tex]P(2\text{ or less than 6\rparen=P\lparen2\rparen+P\lparen less than 6\rparen-P\lparen2 and less than 6\rparen}[/tex]
which gives
[tex]P(2\text{ or less than 6\rparen=}\frac{1}{6}+\frac{5}{6}-\frac{1}{6}=\frac{5}{6}[/tex]
that is because the probability to get a number 2 is 1/6, the probability to get a number less than 6 is 5/6 because there are 5 numbers less than 6 and the probability to get a number 2 and a number less than 6 is 1/6 because there is only one number 2.
Therefore, the answer is:
[tex]\frac{5}{6}[/tex]
