An electric heater of resistance 10.17 Ω draws 18.99 A. If it costs 22¢/kWh, how much will it cost, in pennies, to run the heater for 2.05 h?

Respuesta :

Given:

The resistance of the heater is,

[tex]R=10.17\text{ ohm}[/tex]

The current through the heater is,

[tex]i=18.99\text{ A}[/tex]

The cost per kWh is,

[tex]22\text{ cents}[/tex]

To find:

The cost to run the heater for

[tex]t=2.05\text{ h}[/tex]

Explanation:

The energy used by the heater in this time is,

[tex]\begin{gathered} E=i^2Rt \\ =(18.99)^2\times10.17\times2.05 \\ =7518.39\text{ Wh} \\ =7.52\text{ kWh} \end{gathered}[/tex]

The cost to run the heater is,

[tex]\begin{gathered} 7.52\times22 \\ =165.44\text{ cents} \end{gathered}[/tex]

Hence, the cost to run the heater is 165.44 cents or 165.44 pennies.