Step 1
We will add 1 on both sides of the equation, so we get
originally we had
3x - 1 = 5 but if we add " 1 " we get
3x - 1 + 1 = 5 + 1
so 3x + 0 = 6
and 3x = 6
Step 2
We will now divide by "3" both sides of the equation, so we get
(3x)/3 = 6/3
since (3x)/ 3 = x = 6/3 = 2 ,
we get that our final answer is x = 2.
Now, for the second problem
Step 1
4(2 + x ) = 4*2 + 4x = 8 + 4x = 6 + 6x
So, to summarize we now have
8 + 4x = 6 + 6x,
then we subtract 4x, so
8 + 4x - 4x = 6 + 6x - 4x
so
8 + 0 = 6 + 2x
and
8 = 6 + 2x
now we want to subtract 6
and
8 - 6 = 6 - 6 + 2x
so
2 = 0 + 2x
2 = 2x
and finally we divide both sides by "2" so
2/2 = (2x)/2 = x = 2/2 = 1
and the answer is x = 1
On your paper, it would be enought to write
4(2+x) = 6 + 6x , 8+4x = 6+6x, 2 = 2x , 1 = x.
