Answer:
The new volume of the balloon is 294 cm^3.
Explanation:
The given information from the exercise is:
- Initial volume (V1): 641 cm^3
- Initial temperature (T1): 435 K
- Final temperature (T2): 200 K
To calculate the final volume (V2) of the balloon, we can use the Charles's law formula, by replacing the values of V1, T1 and T2:
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{641cm^3}{435K}=\frac{V_2}{200K} \\ 1.47\frac{cm^3}{K}=\frac{V_{2}}{200K} \\ 1.47\frac{cm^3}{K}*200K=V_2 \\ 294cm^3=V_2 \end{gathered}[/tex]So, the new volume of the balloon is 294 cm^3.
