KanonF504687 KanonF504687
  • 03-11-2022
  • Mathematics
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ements Us Question 4 A 4 in. 65° В Find the area of the sector formed by Z(ABC) in 2 Question Help: 0 Video

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RipkenD302816 RipkenD302816
  • 03-11-2022

Since 65 is equal to 13pi/36, then the area is:

[tex](4^2)(\frac{13\pi}{36})(\frac{1}{2})=8(\frac{13\pi}{36})=\frac{26\pi}{9}=9.076in^2[/tex]

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