Part A:
Part B:
[tex]\begin{gathered} 4\frac{5}{6}=\frac{29}{6} \\ 3\frac{4}{6}=\frac{11}{3} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}=\frac{17}{2}=8\frac{3}{6} \end{gathered}[/tex]Part C:
[tex]\begin{gathered} 3\frac{1}{6}=\frac{19}{6} \\ 2\frac{3}{6}=\frac{15}{6} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}+\frac{19}{6}+\frac{15}{6}=\frac{85}{6}=14\frac{1}{6} \end{gathered}[/tex]Part D:
[tex]\frac{17}{2}-\frac{17}{3}=\frac{17}{6}=2\frac{5}{6}_{}[/tex]