Given:
Numbers in the spinner = 1 to 9 ==> 9 numbers
Possibilities in a coin == Head and tail
Given that you spin the spinner flip a coin then spin the spinner again, let's find the probability of spinning a 4, flipping head, then spinning a 7.
We have the following:
• Probability of spinning a 4:
[tex]P(4)=\frac{1}{9}[/tex]
• Probability of flipping head:
[tex]P(head)=\frac{1}{2}[/tex]
• Probability of spinning a 7:
[tex]P(7)=\frac{1}{9}[/tex]
Hence, we have:
[tex]\begin{gathered} P=P(4)*P(head)*P(9) \\ \\ P=\frac{1}{9}*\frac{1}{2}*\frac{1}{9} \\ \\ P=\frac{1*1*1}{9*2*9} \\ \\ P=\frac{1}{162} \end{gathered}[/tex]
Therefore, the probability is:
[tex]\frac{1}{162}[/tex]
ANSWER:
[tex]\frac{1}{162}[/tex]
