Let's take the total number of students to be 100.
The number of students play football
[tex]\begin{gathered} =\frac{35}{100}\times100 \\ =35 \end{gathered}[/tex]The number of students play basket ball
[tex]\begin{gathered} =\frac{22}{100}\times100 \\ =22 \end{gathered}[/tex]The number of students playing both football and basket ball is
[tex]\begin{gathered} =\frac{15}{100}\times100 \\ =15 \end{gathered}[/tex]By considering the above situation,
From the venn diagram, it is clear that only 7 students play basket ball.
Hence the probability of particular student playing basket ball in winter is
[tex]\begin{gathered} P(\text{basketball)}=\frac{7}{100} \\ =0.0070 \end{gathered}[/tex]
