The graph below is a transformation of f(x)= \frac{1}{4} ^x . Write an equation describing the transformation.As x approaches negative infinity f(x) approaches infinity. As x approaches infinity f(x) approaches 1.(-3,5) is on the graphThe coefficient on our transformed function is AnswerThe exponent on our transformed function is AnswerThe constant we are adding to our function f(x)= \frac{1}{4} ^x is Answer

The graph below is a transformation of fx frac14 x Write an equation describing the transformationAs x approaches negative infinity fx approaches infinity As x class=

Respuesta :

The function is given to be:

[tex]y=\frac{1}{4}^x[/tex]

The graph of the function is shown below:

The graph is shifted up and to the left.

The graph is shifted up by 1 unit. This transformation rule is given to be:

[tex]f(x)\to f(x)+1[/tex]

Therefore, the function becomes:

[tex]y=\frac{1}{4}^x+1[/tex]

The graph is shifted to the left by 2 units. The transformation rule is given to be:

[tex]f(x)\to f(x+2)_{}[/tex]

Therefore, the function becomes:

[tex]y=\frac{1}{4}^{(x+2)}+1[/tex]

To check if the function is correct, we can use the points (-3, 5) if it gives a true statement:

[tex]\begin{gathered} (x,y)=(-3,5) \\ \therefore \\ 5=\frac{1}{4}^{(-3+2)}+1 \\ 5=\frac{1}{4}^{(-1)}+1 \\ 5=4+1 \\ 5=5(\text{True)} \end{gathered}[/tex]

Therefore, the function is:

[tex]y=\frac{1}{4}^{(x+2)}+1[/tex]

The coefficient is 1.

The exponent is x + 2.

The added constant is 1.

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