Answer:
Completing the table, we have;
[tex]\begin{gathered} d\text{ 37 30 23 16 9} \\ t\text{ }\frac{33}{2}\text{ 13 }\frac{19}{2}\text{ 6 }\frac{5}{2} \end{gathered}[/tex]
Explanation:
Given the equation;
[tex]t=\frac{d}{2}-2[/tex]
we want to get the corresponding values of t at each value of d;
let's substitute each of the values of d into the equation and solve for t;
[tex]\begin{gathered} at\text{ d=37;} \\ t=\frac{37}{2}-2=\frac{37-4}{2} \\ t=\frac{33}{2} \end{gathered}[/tex][tex]\begin{gathered} at\text{ d=30;} \\ t=\frac{30}{2}-2=15-2 \\ t=13 \end{gathered}[/tex][tex]\begin{gathered} at\text{ d=23;} \\ t=\frac{23}{2}-2=\frac{23-4}{2} \\ t=\frac{19}{2} \end{gathered}[/tex][tex]\begin{gathered} at\text{ d=16;} \\ t=\frac{16}{2}-2=8-2 \\ t=6 \end{gathered}[/tex][tex]\begin{gathered} at\text{ d=9;} \\ t=\frac{9}{2}-2=\frac{9-4}{2} \\ t=\frac{5}{2} \end{gathered}[/tex]
Therefore, completing the table, we have;
[tex]\begin{gathered} d\text{ 37 30 23 16 9} \\ t\text{ }\frac{33}{2}\text{ 13 }\frac{19}{2}\text{ 6 }\frac{5}{2} \end{gathered}[/tex]
